Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it can trap after raining.
Example 1:
Input: height = [0,1,0,2,1,0,1,3,2,1,2,1] Output: 6 Explanation: The above elevation map (black section) is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rain water (blue section) are being trapped. Example 2:
Input: height = [4,2,0,3,2,5] Output: 9
class Solution {
public int trap(int[] height) {
int left = 0, right = height.length-1;
int left_max = 0, right_max = 0, ans = 0;
while(left < right){
if(height[left] < height[right]){
if(height[left] > left_max){
left_max = height[left];
} else{ //低窪
ans += left_max - height[left];
}
left++;
} else{
if(height[right] > right_max){
right_max = height[right];
} else{
ans += right_max - height[right];
}
right--;
}
}
return ans;
}
}
Time: O(n) Space: O(1)